2021-08-16 笔试情况

题目：编写一个编译器，结算内存所需要的字节数  
请输入一个字符串，编译出代码所需要的字节数，如：int a[10][10][10],k,m; 
int 类型所占4个字节
long 类型所占8个字节
char 类型所占1个字节

输入描述：
int a[10][10][10],k,m;  
输出描述：
输入格式为 变量类型+一个空格+变量；
输出结果：
4008
(10 x 10 x 10 + 1 + 1) x 4 = 4008

个人写的很丑很臭代码：

package kaoshi;
import java.util.Arrays;
import java.util.Scanner;

/**
 * @author 王一宁
 * @date 2021/8/16 18:34
 * 【供阿里笔试 考试使用】
 */
public class KaoShi {
    public static void main(String[] args) {
        int res = 0; //定义字节数
        Scanner sc = new Scanner(System.in);
        String s = sc.nextLine();
        String substring = s.substring(0, s.length() - 1);
        String[] chars1 = substring.split(" ");

        // 切割chars1
        String[] splitchars1 = chars1[1].split(",");
        String stringnum = "";
        int num = 0; // 数组乘几次
        int baseNum = 0;// 求次方的底数

        if (chars1[1].contains("[")){
            for (int i = 0; i < splitchars1.length; i++) {
                if (splitchars1[i].contains("[")){
                    stringnum = splitchars1[i];
                }
            }
            int i1 = stringnum.indexOf("[");
            System.out.println("第一次出现 [ 的下标: "+i1);
            int i2 = stringnum.indexOf("]");
            System.out.println("第一次出现 ] 的下标: "+i2);
            String substringnum = stringnum.substring(i1 + 1, i2);
            baseNum = Integer.parseInt(substringnum);
            System.out.println("i3的数值为: "+baseNum);
            if (chars1[0].equals("int")) {
                for (int i = 0; i < stringnum.length(); i++) {
                    char c = stringnum.charAt(i);
                    if (c == '['){
                        num = num + 1;
                    }
                }
                System.out.println("数值部分需要进行几次乘积："+num);
                baseNum = (int) Math.pow(baseNum,num);
                res = (baseNum + splitchars1.length-1)*4;
                System.out.println("最终字节大小为: "+ res);
            }else if(chars1[0].equals("long")){
                for (int i = 0; i < stringnum.length(); i++) {
                    char c = stringnum.charAt(i);
                    if (c == '['){
                        num = num + 1;
                    }
                }
                System.out.println("数值部分需要进行几次乘积："+num);
                baseNum = (int) Math.pow(baseNum,num);
                res = (baseNum + splitchars1.length-1)*8;
                System.out.println("最终字节大小为: "+ res);
            }else {
                for (int i = 0; i < stringnum.length(); i++) {
                    char c = stringnum.charAt(i);
                    if (c == '['){
                        num = num + 1;
                    }
                }
                System.out.println("数值部分需要进行几次乘积："+num);
                baseNum = (int) Math.pow(baseNum,num);
                res = baseNum + splitchars1.length-1;
                System.out.println("最终字节大小为: "+ res);
            }

        }else{
            if (chars1[0].equals("int")){
                res = splitchars1.length * 4;
                System.out.println(res);
            }else if (chars1[0].equals("long")){
                res = splitchars1.length * 8;
                System.out.println(res);
            }else if (chars1[0].equals("char")){
                res = splitchars1.length;
                System.out.println(res);
            }
        }
    }
}

输出结果测试：