class Solution {
public:
ListNode* Merge(ListNode* pHead1, ListNode* pHead2) {
auto dummy = new ListNode(-1); //定义一个虚拟表头
auto cur = dummy; //定义一个移动节点
while (pHead1 && pHead2) { //遍历
if (pHead1->val < pHead2->val) { //小的数放前面
cur->next = pHead1; //1->3
pHead1 = pHead1->next;
}
else {
cur->next = pHead2; //1->3
pHead2 = pHead2->next;
}
cur = cur->next;
}
if (pHead1) cur->next = pHead1; //因为最后总会多一个数,无法进行比较的
else cur->next = pHead2; //所以那个链表多了就放那个链表中的数到最后
return dummy->next;
}
};
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