判断线段是否有重叠部分

import java.util.ArrayList;
import java.util.Scanner;
//线段是否有重复 送分签到题 暴力解决
public class Main1 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        ArrayList arrayList = new ArrayList(n);
        for (int i = 0; i < n; i++) {
            int l = sc.nextInt();
            int r = sc.nextInt();
            arrayList.add(new Line(l, r));
        }
        arrayList.sort((a, b) -> (a.l - b.l));
        boolean contain = false;
        for (int i = 1; i < n; i++) {
            Line line1 = arrayList.get(i);
            for (int j = 0; j < i; j++) {
                Line line2 = arrayList.get(j);
                if(line1.l<=line2.l && line2.r <= line1.r){
                    contain = true;
                    break;
                }
            }
            if(contain){
                break;
            }
        }
        String res = contain ? "true" : "false";
        System.out.println(res);
    }
    static class Line  {
        int l;
        int r;
        public Line(int l, int r) {
            this.l = l;
            this.r = r;
        }
    }
}

暴力模拟 出牌过程 游戏规则类似于钓鱼的打法https://zhidao.baidu.com/question/989309794876569339.html

import java.util.*;

public class Main2 {
    //纸牌游戏 钉钩钓鱼
    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        HashSet<Integer> set = new HashSet<>();
        int[] a = new int[n];
        int[] b = new int[n];
        for (int i = 0; i < n; i++) {
            a[i] = sc.nextInt();
        }
        for (int i = 0; i < n; i++) {
            b[i] = sc.nextInt();
        }
        LinkedList<Integer> list = new LinkedList<>();
        int indexA = 0;
        int indexB = 0;
        int countA = 0;
        int countB = 0;
        boolean isA = true;
        while (indexA <= n && indexB <= n) {
            if (indexA == n && indexB == n) {
                break;
            }
            isA = (isA && indexA < n) || indexB == n;
            int num = isA  ? a[indexA] : b[indexB];
            if (isA) {
                indexA++;
            } else {
                indexB++;
            }
            int count = 0;
            if (set.contains(num)) {
                while (list.getLast() != num) {
                    int temp = list.getLast();
                    list.removeLast();
                    set.remove(temp);
                    count++;
                }
                count+=2;
                set.remove(list.getLast());
                list.removeLast();
                if (isA) {
                    countA += count;
                } else {
                    countB += count;
                }
                continue;
            } else {
                list.add(num);
                set.add(num);
            }
            isA = !isA;
        }
        for (Integer i : list) {
            if (i % 2 == 1) {
                countA++;
            } else {
                countB++;
            }
        }
        System.out.println(countA + " " + countB);

    }
}

数学题 判断 对于给定的A，B，C 是否存在大于等于0的整数m,n 满足C^m*A+nB = q

import java.util.Scanner;

public class Main3 {
    // C^n*A+m*B
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int T = sc.nextInt();
        for (int i = 0; i < T; i++) {
            long a = sc.nextInt();
            long b = sc.nextInt();
            long c = sc.nextInt();
            long q = sc.nextInt();
            long index = 0;
            boolean can = false;
            while (true) {
                long count = 1;
                for (int j = 0; j < index; j++) {
                    count *= c;
                }
                index++;
                long temp = a * count;
                if (temp > q) {
                    break;
                }
                can = (q - temp) % b == 0;
                if (can) {
                    break;
                }
                if(c==1){
                    break;
                }
            }
            System.out.println(can ? 1 : 0);
        }
    }
}

第四题 没有搞懂 感觉自己的做法没有问题 给一堆数字 怎么组合使得乘积最大 只过了16% 不知道原因

import java.math.BigDecimal;
import java.math.BigInteger;
import java.util.Scanner;

public class Main4 {
    //一堆数字 如何排列组合使得结果最大
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        //9876 5432 54646432 84
        //大数字相乘
        int[] nums = new int[10];
        for (int i = 0; i < 10; i++) {
            nums[i] = sc.nextInt();
        }
        int maxIndex = 9;
        StringBuilder sb1 = new StringBuilder();
        StringBuilder sb2 = new StringBuilder();
        int c = 0;
        while (maxIndex > 0) {
            if (nums[maxIndex] > 0) {
                int n = nums[maxIndex] / 2;
                for (int i = 0; i < n; i++) {
                    sb1.append(maxIndex);
                    sb2.append(maxIndex);
                }
                nums[maxIndex] -= n * 2;
                c += n * 2;
                if (nums[maxIndex] > 0) {
                    if (c % 2 == 0) {
                        sb1.append(maxIndex);
                    } else {
                        sb2.append(maxIndex);
                    }
                    c += 1;
                }
            }
            maxIndex--;
        }
        String s1 = sb1.toString();
        String s2 = sb2.toString();
        BigInteger b1 = new BigInteger(s1);
        BigInteger b2 = new BigInteger(s2);
        BigInteger res = b1.multiply(b2);
        if(res.equals(BigInteger.ZERO)){
            System.out.println("0");
            return;
        }
        String ans = res.toString();
        StringBuilder sb = new StringBuilder();
        for (int i = 0; i < nums[0]; i++) {
            sb.append("0");
        }
        ans = ans + sb;
        System.out.println(ans);
    }
}