Suppose that a shared variable total (initialized as 0 ) can be accessed by the process P0 and P1. If the following processes execute concurrently, what is the probable minimum result of total?
P1:
{
int count;
for ( count =1; count <= 50; count++ )
total = total + 1;
}
P2:
{
int count;
for ( count =1; count <= 50; count++ )
total = total + 1;
}
有可能先 total + 1;寄存器里放了个1，然后跑到p2了，这时候total还没变成2，他又total+1，寄存器是2，但是count没变，就一直这样，[1]
[1]但是count 也不会++了啊，count++的前提是 total 那句已经做过了，确实
(1分)
A.1
B.2
C.3
D.50
答案是 B 2，但是有具体过程吗，球球
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