String Function Encoding
题号:NC24691
时间限制:C/C++/Rust/Pascal 1秒,其他语言2秒
空间限制:C/C++/Rust/Pascal 32 M,其他语言64 M
64bit IO Format: %lld

题目描述

Bessie discovered a new function that the entire herd can apply to its character strings.
Given both a number N (1 <= N <= 15) and a string S, with length strictly greater than N, define f(N, S) as a new string composed of the concatenation of the substring from character N (zero based -- first character is number 0) through the end of S and the string S itself.
For example, with N = 2, and S = "COW", f(N, S) = "W" + "COW" = "WCOW". Also, f(3, "USACO") = "CO" + "USACO" = "COUSACO".
Bessie is enthralled with this function and wants to iterate it several times. For example, if she iterates the function once for "COW" and N = 2, she will get "WCOW". If she applies the function with N = 2 again to that string, she will get "OWWCOW", and if she applies it one more time with N = 2, she will get "WCOWOWWCOW".
Help Bessie encode a total of Z (1 <= Z <= 100) strings, str_1, str_2, and so on. Each str_i has length in the range 2..100 and contains only upper case letters. Each string is presented with its own N_i (0 <= N_i < length(str_i), and iteration count C_i (1 <= C_i <= 12).

输入描述:

* Line 1: A single integer: Z
* Lines 2..Z+1: Line i+1 contains two space-separated integers, a space, and string to be encoded: N_i, C_i, and str_i

输出描述:

* Lines 1..Q: Line j contains the iterated, encoded version of str_j
示例1

输入

复制
2
2 3 COW
3 2 USACO

输出

复制
WCOWOWWCOW
SACOCOUSACO

说明

The arrow denotes an iteration of the function
COW -> WCOW -> OWWCOW -> WCOWOWWCOW
USACO -> COUSACO -> SACOCOUSACO