[USACO 2013 Mar S]The Cow run
题号:NC24400
时间限制:C/C++/Rust/Pascal 1秒,其他语言2秒
空间限制:C/C++/Rust/Pascal 32 M,其他语言64 M
64bit IO Format: %lld

题目描述

Farmer John has forgotten to repair a hole in the fence on his farm, and his N cows (1 <= N <= 1,000) have escaped and gone on a rampage! Each minute a cow is outside the fence, she causes one dollar worth of damage. FJ must visit each cow to install a halter that will calm the cow and stop the damage. 
Fortunately, the cows are positioned at distinct locations along a straight line on a road outside the farm. FJ knows the location P_i of each cow i (-500,000 <= P_i <= 500,000, P_i != 0) relative to the gate (position 0) where FJ starts. 
FJ moves at one unit of distance per minute and can install a halter instantly. Please determine the order that FJ should visit the cows so he can minimize the total cost of the damage; you should compute the minimum total damage cost in this case.

输入描述:

* Line 1: The number of cows, N.

* Lines 2..N+1: Line i+1 contains the integer P_i.

输出描述:

* Line 1: The minimum total cost of the damage.
示例1

输入

复制
4
-2
-12
3
7

输出

复制
50

说明

INPUT DETAILS:
Four cows placed in positions: -2, -12, 3, and 7.

OUTPUT DETAILS:
The optimal visit order is -2, 3, 7, -12. FJ arrives at position -2 in 2
minutes for a total of 2 dollars in damage for that cow.
He then travels to position 3 (distance: 5) where the cumulative damage is
2 + 5 = 7 dollars for that cow.
He spends 4 more minutes to get to 7 at a cost of 7 + 4 = 11 dollars for
that cow.
Finally, he spends 19 minutes to go to -12 with a cost of 11 + 19 = 30 dollars.
The total damage is 2 + 7 + 11 + 30 = 50 dollars.