Lady Layton with Math
题号:NC200008
时间限制:C/C++/Rust/Pascal 5秒,其他语言10秒
空间限制:C/C++/Rust/Pascal 256 M,其他语言512 M
64bit IO Format: %lld

题目描述

Lady Layton has a problem about math.
She will give you a integer n, please calculate .

输入描述:

The first line contains one integer T(1<=T<=10)— the number of test cases.
The only line of each test case contains one integers n() — the integer of she give.

输出描述:

For each test case print the answer modulo  in one line.
示例1

输入

复制
3
10
100
1000

输出

复制
136
21012
2914160

备注:

In mathematics, the greatest common divisor (gcd) of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers. For example, .
In number theory, be called Euler's phi function, it is the number of integers k (1<=k<=n) which .