Divisors
时间限制:C/C++/Rust/Pascal 2秒,其他语言4秒
空间限制:C/C++/Rust/Pascal 256 M,其他语言512 M
64bit IO Format: %lld

题目描述

Bizon the Champion isn't just friendly, he also is a rigorous coder.

Let's define function f(a), where a is a sequence of integers. Function f(a) returns the following sequence: first all divisors of a1 go in the increasing order, then all divisors of a2 go in the increasing order, and so on till the last element of sequence a. For example, f([2, 9, 1]) = [1, 2, 1, 3, 9, 1].

Let's determine the sequence Xi, for integer i(i ≥ 0): X0 = [X] ([X] is a sequence consisting of a single number X), Xi = f(Xi - 1)(i > 0). For example, at X = 6 we get X0 = [6], X1 = [1, 2, 3, 6], X2 = [1, 1, 2, 1, 3, 1, 2, 3, 6].

Given the numbers X and k, find the sequence Xk. As the answer can be rather large, find only the first 105 elements of this sequence.

输入描述:

A single line contains two space-separated integers — X(1 ≤ X ≤ 1012) and k(0 ≤ k ≤ 1018).

输出描述:

Print the elements of the sequence Xk in a single line, separated by a space. If the number of elements exceeds 105, then print only the first 105 elements.

示例1

输入

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6 1

输出

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1 2 3 6
示例2

输入

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4 2

输出

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1 1 2 1 2 4
示例3

输入

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10 3

输出

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1 1 1 2 1 1 5 1 1 2 1 5 1 2 5 10