Cow Sorting
时间限制:C/C++/Rust/Pascal 2秒,其他语言4秒
空间限制:C/C++/Rust/Pascal 64 M,其他语言128 M
64bit IO Format: %lld

题目描述

Farmer John's N (1 ≤ N ≤ 10,000) cows are lined up to be milked in the evening. Each cow has a unique "grumpiness" level in the range 1...100,000. Since grumpy cows are more likely to damage FJ's milking equipment, FJ would like to reorder the cows in line so they are lined up in increasing order of grumpiness. During this process, the places of any two cows (not necessarily adjacent) can be interchanged. Since grumpy cows are harder to move, it takes FJ a total of X+Y units of time to exchange two cows whose grumpiness levels are X and Y.

Please help FJ calculate the minimal time required to reorder the cows.

输入描述:

Line 1: A single integer: N.
Lines 2.. N+1: Each line contains a single integer: line i+1 describes the grumpiness of cow i.

输出描述:

Line 1: A single line with the minimal time required to reorder the cows in increasing order of grumpiness.
示例1

输入

复制
3
2
3
1

输出

复制
7

备注:

2 3 1 : Initial order.
2 1 3 : After interchanging cows with grumpiness 3 and 1 (time=1+3=4).
1 2 3 : After interchanging cows with grumpiness 1 and 2 (time=2+1=3).