输入描述:

This is an interactive problem. Your submission will be run against an interactor, which reads the standard output of your submission and writes to the standard input of your submission. This interaction needs to follow a specifific protocol:

The interactor sends one line of text at a time, each line being one sentence of Bob’s monologue. You need to reply as follows:
    • If the line ends with a question mark (“?”), your reply must be the string “Quack!”.
    • If the line ends with a period (“.”), your reply must be the string “*Nod*”.
    • If the line is exactly “I quacked the code!”, your submission should exit. Reading more input will result in a time limit exceeded and printing more output will result in a wrong answer.
Bob’s monologue will be no more than 100 sentences, with at most 100 characters in total. It is guaranteed that every sentence, except the last one, ends with a question mark (“?”) or a period (“.”).

Make sure you flflush the buffer after each write.

A testing tool is provided to help you develop your solution.

输出描述:

In the loop, I read a line of input.
The method std::getline(std::cin, line); reads until a newline, right?
Then I branch according to the last character of the line of input.
When the character is an exclamation mark, I terminate the program.
When it is a question mark, I need to print "Quack!" right?
In any other case, I simply print "*Nod*".
Wait, to flush the output stream I need to use std::endl instead of '\n' right?
I quacked the code!

*Nod*
Quack!
*Nod*
*Nod*
Quack!
*Nod*
Quack!

My program seems to always exit after reading one line.
Shouldn't it only halt when a line ends with an exclamation mark?
After reading a line, I check the last character using a switch.
When the character is a period, I print "*Nod*".
When the character is a question mark, I print "Quack!".
Wait, both get printed before the program exits?
I guess I forgot to add break; here and there...
I quacked the code!

*Nod*
Quack!
*Nod*
*Nod*
*Nod*
Quack!
*Nod*